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Aptitude
In covering a distance of 30 km, A takes 2 hours more than B. If A doubles his speed, then he would take 1 hour less than B. A's speed is:
5 1/4km/hr
5km/hr
8km/hr
6km/hr
Walking at the rate of 4kmph a man cover certain distance in 2hr 45 min. Running at a speed of 16.5 kmph the man will cover the same distance in.
39min.
47min.
40min.
41min.
Answer : 3.
Time= 2hr 45min = `2 45/60 hr = 2 3/4 hr = 11/4 hr`Distance = Speed * time`4*11/4 = 11km`New Speed = 16.5 kmphTherefore `"time" = "Distance"/"Speed" = 11/16.5 = 40min`
Two monkeys starting from the same place walk at a rate of 5kmph and 5.5kmph respectively. What time will they take to be 8.5km apart, if they walk in the same direction?
17hrs.
18hrs.
17 1/30hrs.
16hrs.
Answer : 1.The relative speed of the boys = 5.5kmph – 5kmph= 0.5 kmphDistance between them is 8.5 kmTime= `"8.5km"/"0.5 kmph" = 17 hrs`
A man covers a distance on scooter. Had he moved 3kmph faster he would have taken 40 min less. If he had moved 2kmph slower, he would have taken 40min more. The distance is?
40km.
41km.
35km.
39km.
Answer : 1.Let distance = x m Usual rate = y kmph `x/y – x/(y+3) = 40/60 hr` 2y(y+3) = 9x ---------------------------------(1)
`x/(y-2) – x/y = 40/60 hr` y(y-2) = 3x -----------(2)
divide 1 & 2 equations by solving we get x = 40 km
A motorist covers a distance of 39km in 45min by moving at a speed of x kmph for the first 15min, then moving at double the speed for the next 20 min, and then again moving at his original speed for the rest of the journey. Find x.?
36km/hr.
35km/hr.
37km/hr.
34km/hr.
Answer : 1.Total distance = 39 km Total time = 45 min D = S*T `x * 15/60 + 2x * 20/60 + x * 10/60 = 39 km `x = 36 kmph
A & B are two towns. A person covers the distance from A to B on cycle at 17kmph and returns to A by a boat running at a uniform speed of 8kmph. His average speed for the whole journey is?
10.88kmph.
10.99kmph.
10kmph.
12.33kmph.
Answer : 1.When same distance is covered with different speeds, then the average speed = `(2 * x * y) / (x + y)` = 10.88kmph
A car covers 4 successive 3km stretches at speed of 10kmph, 20kmph, 30kmph & 60kmph resp. Its average speed is?
20kmph.
30kmph.
25kmph.
27kmph.
Average speed = total distance / total time total distance = 4 * 3 = 12 km total time = `3/10 + 3/20 + 3/30 + 3/60` = `36/60` hr speed =`12/(36 / 60)` = 20 kmph
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