What is the output of the following code? int i = 0; int j = 10; do { if (i++

Question

What is the output of the following code? int i = 0; int j = 10; do { if (i++ < --j) { // Empty block } } while (i < 5);

Accepted Answer

The output of the code is 9.

The code initializes i as 0 and j as 10.
Inside the do-while loop, i is incremented by 1 and j is decremented by 1.
The loop continues until i becomes greater than or equal to j.
Since i is incremented before the comparison and j is decremented before the comparison, the loop runs 9 times.
Therefore, the output is 9.

Accepted Answer

The code snippet you provided seems to be incomplete. The while loop condition is cut off.

If the incomplete part is "while(i

int i = 0;

int j = 10;

do {

if (i++ < --j) {

// Code block inside the if statement (not specified in the question)

}

} while (i < j);

In this revised code, the do-while loop will continue executing as long as the condition i < j is true. The code block inside the loop will only be executed if the condition i++ < --j evaluates to true.

What is the output of the following code? int i = 0; int j = 10; do { if (i++ < --j) { // Empty block } } while (i < 5);

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What is the output of the following code? int i = 0; int j = 10; do { if (i++ < --j) { // Empty block } } while (i < 5);