10+ Rosemallow Interview Questions and Answers

Find the maximum sum of any contiguous subarray within an array in O(N) time complexity.

• Use Kadane's algorithm to find the maximum sum subarray in O(N) time complexity

• Initialize two variables: max_sum and current_sum to keep track of the maximum sum subarray

• Iterate through the array and update current_sum by adding the current element or starting a new subarray

• Update max_sum if current_sum is greater than max_sum

• Return max_sum as the maximum sum of any contiguous subarray

The problem involves finding the total number of unique paths from the top-left to bottom-right cell of a matrix by moving only right or down.

• Use dynamic programming to solve the problem efficiently.

• Create a 2D array to store the number of unique paths at each cell.

• Initialize the first row and first column with 1 as there is only one way to reach them.

• For each cell (i, j), the number of unique paths is the sum of paths from the cell above and the cell to the left.

• Return the v...read more

Check if Ninja can cross the river by jumping from one safe segment to another based on given constraints.

• Iterate through the 'SAFE' array and check if Ninja can make the required jumps to reach the last safe segment.

• Ensure that the next jump is either 'X' - 1, 'X', or 'X' + 1 units from the previous jump.

• Return 'true' if Ninja can successfully cross the river, otherwise return 'false'.

Given a tree with N nodes, find the number of elements in each subtree rooted at every node.

• Traverse the tree using Depth First Search (DFS) to calculate subtree sizes for each node.

• Use an array to store subtree sizes for each node, starting with leaf nodes having size 1.

• The subtree size of a node is the sum of subtree sizes of its children plus 1 for the node itself.

The task is to print the left view of a binary tree, which contains the nodes visible when the tree is viewed from the left side.

• Traverse the tree in a level order manner and keep track of the leftmost node at each level.

• Use a queue to perform level order traversal.

• Print the leftmost node at each level to get the left view of the binary tree.

Return the middle element of a singly linked list, or the one farther from the head if there are even elements.

• Traverse the linked list with two pointers, one moving twice as fast as the other

• When the fast pointer reaches the end, the slow pointer will be at the middle

• Return the element pointed to by the slow pointer

CHAR is fixed length while VARCHAR2 is variable length in SQL.

• CHAR stores fixed length strings, padding with spaces if necessary.

• VARCHAR2 stores variable length strings, not padding with spaces.

• CHAR is faster for fixed length data, VARCHAR2 is more flexible for varying length data.

Design a Doctor Appointment System with test cases

• Create a database to store doctor information, patient information, and appointment details

• Implement a user interface for patients to schedule appointments with available doctors

• Include features like appointment reminders, cancellation, and rescheduling

• Test cases: 1. Schedule appointment successfully 2. Cancel appointment 3. Reschedule appointment

Overloading is having multiple methods in the same class with the same name but different parameters, while overriding is implementing a method in a subclass that is already defined in the superclass.

• Overloading involves multiple methods with the same name but different parameters.

• Overriding involves implementing a method in a subclass that is already defined in the superclass.

• Overloading is resolved at compile time based on the method signature, while overriding is resolved ...read more

There are three types of constructors in C++: default constructor, parameterized constructor, and copy constructor.

• Default constructor: Constructor with no parameters.

• Parameterized constructor: Constructor with parameters.

• Copy constructor: Constructor that initializes an object using another object of the same class.

• Example: // Default constructor ClassName() {} // Parameterized constructor ClassName(int x, int y) : x(x), y(y) {} // Copy constructor ClassName(const ClassName&...read more

The API allows users to retrieve weather data based on location.

• Create a new endpoint that accepts a location parameter

• Use a weather API service to fetch weather data based on the location

• Return the weather data in a standardized format, such as JSON