Find the Second Largest Element

Given an array or list of integers 'ARR', identify the second largest element in 'ARR'.

If a second largest element does not exist, return -1.

Example:

Input:

ARR = [2, 4, 5, 6, 8]

Output:

6

Explanation:

In the sequence, 8 is the largest and 6 is the second largest.

Input:

ARR = [5, 5, 5, 5, 5]

Output:

-1

Explanation:

There is no second largest element as all elements are identical.

Constraints:

1 ≤ T ≤ 100 where 'T' is the number of test cases.

1 ≤ N ≤ 5000 where 'N' is the number of elements in 'ARR'.

-10^9 ≤ ARR[i] ≤ 10^9 for each element in 'ARR'.

Note:

You do not need to print any output. Implement the function to return the desired results.

Question

Find the Second Largest Element

Given an array or list of integers 'ARR', identify the second largest element in 'ARR'.

If a second largest element does not exist, return -1.

Example:

Input:

ARR = [2, 4, 5, 6, 8]

Output:

Explanation:

In the sequence, 8 is the largest and 6 is the second largest.

Input:

ARR = [5, 5, 5, 5, 5]

Output:

-1

Explanation:

There is no second largest element as all elements are identical.

Constraints:

1 ≤ T ≤ 100 where 'T' is the number of test cases.
1 ≤ N ≤ 5000 where 'N' is the number of elements in 'ARR'.
-10^9 ≤ ARR[i] ≤ 10^9 for each element in 'ARR'.

Note:

You do not need to print any output. Implement the function to return the desired results.

Accepted Answer

The task is to find the second largest element in an array of integers.

Iterate through the array and keep track of the largest and second largest elements.
Initialize the largest and second largest variables with the first two elements of the array.
Compare each element with the largest and second largest variables and update them accordingly.
Return the second largest element at the end.
Handle the case where no second largest element exists.

Accepted Answer

li.stream().distinct()
				.sorted(Comparator.reverseOrder()).skip(1).findFirst()
				.ifPresentOrElse(
					      value -> System.out.println("Second largest element: " + value),  
					      () -> System.out.println("-1") 
					  );

Accepted Answer

asuming element (4 6 9 3)

here 2nd largest element is 6