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Find the Duplicate Number Problem Statement
Given an integer array 'ARR' of size 'N' containing numbers from 0 to (N - 2). Each number appears at least once, and there is one number that appears twice. Your task is to find and return this duplicate number.
Example:
Input:
t = 1
N = 5
ARR = [0, 3, 1, 2, 3]
Output:
3
Explanation:
The number '3' is the duplicate because it appears twice in the array.
Constraints:
1 <= t <= 10^2
0 <= N <= 10^3
- Time Limit: 1 sec
Note:
The duplicate number is always present in the given array.
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Given an array of size N containing numbers from 0 to (N-2), find and return the duplicate number.
Iterate through the array and keep track of the frequency of each number using a hashmap.
Return the nu...read more
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Duplicate values are not allowed
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List not allowed duplicate values
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List not allowed duplicate values
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<include>http,
if
int array size 'N';
else,number 0 to (N-2);
goto (if) (else)
do
number presentt once,
print,N=5,;
while,array ranging 0 to3,
and
if single integers present twice,;
goto,if else;
(break) the numb...read more
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Set unique = new HashSet();
List duplicateList = Arrays.of(inputArray);
duplicateList.stream().filter(s-> !unique.add(s)).forEach(System.out.println);
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Sure, I can help you with that. Here is the algorithm to find the duplicate number in an array:
Iterate through the array and create a set of all the elements in the array.
Iterate through the set and c...read more
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