Lantronix India Pvt. Ltd., Senior Software Engineer Interview Questions and Answers

Q1. Reverse linked list using the recursion
Ans. 
Reverse a linked list using recursion
• Create a recursive function that takes the head of the linked list as input

• Base case: if the head is null or the next node is null, return the head

• Recursively call the function with the next node as input

• Set the next node's next pointer to the current node

• Set the current node's next pointer to null

• Return the new head of the reversed linked list
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Q2. Find max number in the linked list using stack.
Ans. 
To find max number in linked list using stack.
• Create an empty stack.

• Traverse the linked list and push each element onto the stack.

• Pop elements from the stack and compare with max value.

• Return the max value.
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Aptitude relates questions... It was modratley difficult

Q1. Twchnical rouns. Qas easy... Asked questions oc C and some. Projects
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Q2. Reverse linked list using recursion
Ans. 
Reverse a linked list using recursion
• Create a recursive function that takes the head of the linked list as input

• Base case: if the head is null or the next node is null, return the head

• Recursively call the function with the next node as input

• Set the next node's next pointer to the current node

• Set the current node's next pointer to null

• Return the new head of the reversed linked list
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Q3. What is difference between mutex semaphore?
Ans. 
Mutex is a locking mechanism to ensure exclusive access to a shared resource, while semaphore is a signaling mechanism to control access to a shared resource.
• Mutex allows only one thread to access the shared resource at a time, while semaphore can allow multiple threads to access the shared resource simultaneously.

• Mutex is binary, meaning it has only two states - locked and unlocked, while semaphore can have multiple s...read more
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Hacker rank codinv problems level medium

Q1. Coding round again D and S
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Q1. System design tech dummies
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Q1. Common questions , why we should hire you , achievements
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Checked general aptitude

Multiple coding rounds each tougher than the last

Q1. Mostly related to Python and Kubernetes
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Q1. Mostly related to salaries
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Q1. Explain 3G call flow
Ans. 
3G call flow involves multiple steps including network registration, call setup, and data transfer.
• User equipment (UE) registers with the network by sending a Location Update Request.

• Network authenticates the UE and assigns it a temporary identity.

• UE initiates a call by sending a Setup Request to the network, which then establishes a connection with the called party.

• Data transfer occurs between the two parties over the...read more
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Q2. Explain 23 to 3G handover
Ans. 
23 to 3G handover is a process where a mobile device switches from a 2G network to a 3G network for better data speeds and coverage.
• Handover process involves the mobile device connecting to a new network while maintaining the ongoing call or data session.

• The switch from 2G to 3G network is triggered based on factors like signal strength, network congestion, and data speed requirements.

• During handover, the mobile device...read more
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Q1. Networking related questions
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Q1. Location & compensation related
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Q1. Make Kanbon board in react live coding
Ans. 
Create a Kanban board in React during live coding interview
• Use React components to represent different sections of the Kanban board (e.g. To Do, In Progress, Done)

• Implement drag and drop functionality for moving tasks between sections

• Utilize state management (e.g. useState) to track the tasks and their statuses

• Style the board using CSS or a UI library like Material-UI
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Q2. Write unit testing for the same
Ans. 
Unit testing is a software testing method where individual units or components of a software are tested in isolation.
• Identify the unit to be tested

• Write test cases to cover different scenarios

• Use testing frameworks like JUnit or NUnit

• Mock external dependencies for isolated testing
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Two problems, one easy and another medium level.

Q1. One linked list Problem
Ans. 
Reverse a linked list
• Iterate through the linked list and reverse the pointers

• Use three pointers to keep track of current, previous, and next nodes

• Update the pointers accordingly to reverse the list
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Q2. Questions on project and solutions we porvided
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Q1. About the current project
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Q2. Some behavioural questions
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2 coding questions in c/c++, 1 hr 30 mins - no. of deletions/additions needed to make 1 string equal to another. 2. print frequency of each number in array

One take home assignment

Q1. Questions on JS basics
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Q2. Angular deep dive
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Q1. General discussion with hiring manager
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