Write a code to find if two words are anagrams

Question

Accepted Answer

Code to check if two words are anagrams

Convert both words to lowercase
Remove all spaces and punctuation
Sort the characters in both words
Compare the sorted words

Accepted Answer

import string

class AnagramChecker:

def init(self, word1, word2):

self.word1 = word1

self.word2 = word2

def preprocessword(self, word):

word = word.lower()

word = word.translate(str.maketrans('', '', string.punctuation + ' '))

return word

def sortword(self, word):

sorted_word = ''.join(sorted(word))

return sorted_word

def are_anagrams(self):

try:

word1_cleaned = self._preprocess_word(self.word1)

word2_cleaned = self._preprocess_word(self.word2)

sorted_word1 = self._sort_word(word1_cleaned)

sorted_word2 = self._sort_word(word2_cleaned)

return sorted_word1 == sorted_word2

except Exception as e:

print(f"An error occurred: {e}")

return False

anagram_checker = AnagramChecker("Listen", "Silent")

print(anagram_checker.are_anagrams())

anagram_checker = AnagramChecker("hello", "world")

print(anagram_checker.are_anagrams())

anagram_checker = AnagramChecker("Astronomer", "Moon starer")

print(anagram_checker.are_anagrams())

Accepted Answer

def are_anagrams(word1, word2):

word1 = word1.replace(" ", "").lower()

word2 = word2.replace(" ", "").lower()

if len(word1) != len(word2):

return False

char_freq1 = {}

char_freq2 = {}

for char in word1:

char_freq1[char] = char_freq1.get(char, 0) + 1

for char in word2:

char_freq2[char] = char_freq2.get(char, 0) + 1

return char_freq1 == char_freq1

print(are_anagrams("listen", "silent"))

print(are_anagrams("hello", "world"))

print(are_anagrams("schoolmaster", "the classroom"))

print(are_anagrams("anaconda", "bandana"))

Accepted Answer

public boolean isAnagram(String s, String t) {
    char[] sortedS = Arrays.sort(s.toCharArray());
    char[] sortedT = Arrays.sort(t.toCharArray());

    return Arrays.equals(sortedS, sortedT);
}

Accepted Answer

ArrayList ee=new ArrayList(String);

for(int i=0;i

{

ee.add(s1.charAt(i));

}

int c=0;

for(int i=0;i

{

if(ee.contains(s2.charAt(i))

{

c++;

}}

if(c==s1.length())

System.out.print("Anagram");

else

System.out.println("Not anagram");

}

Write a code to find if two words are anagrams

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