main ( ) { unsigned int i=3; while( i =0) printf( "%d", i--); } How many times will the printf stmt be executed? a) 0 b) 3 c) 4 d) infinite Ans: I think the answer is infinite, because 'i' is an unsigned integer and it will not decrement below '0' And hence end up in an infinite loop. (Yes, i checked and it is getting stuck in an infinite loop)

Question

main ( ) { unsigned int i=3; while( i >=0) printf( "%d", i--); } How many times will the printf stmt be executed? a) 0 b) 3 c) 4 d) infinite Ans: I think the answer is infinite, because 'i' is an unsigned integer and it will not decrement below '0' And hence end up in an infinite loop. (Yes, i checked and it is getting stuck in an infinite loop)

Accepted Answer

The printf statement will be executed 4 times.

The initial value of 'i' is 3.
In each iteration of the while loop, 'i' is decremented by 1.
The loop will continue until 'i' becomes less than 0.
Therefore, the printf statement will be executed 4 times.

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