Given an n x n matrix, where every row and column is sorted in increasing order, how do you decide whether a given number x is in the matrix with linear time complexity?

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2y

Algorithm to find if a number is present in a sorted n x n matrix with linear time complexity.

  • Start with the top right element

  • Compare the element with x

  • If equal, return its position

  • If e < x, move down...read more

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