Black Friday Discount Challenge
Imagine it's Black Friday and a supermarket is offering a discount to every 'Nth' customer. You are tasked with calculating bills for customers based on product prices and quantities, factoring in potential discounts for specific customers.
Function Descriptions:
blackFriday(int N, int discount, int[] products, int[] prices)
: Initializes with every Nth customer receiving a discount, 'discount' is the percentage, 'products' array contains product IDs, and 'prices' array has product prices.generateBill(int[] productID, int[] quantity)
: Takes 'productID' and 'quantity' arrays to calculate the total bill for each customer's purchase.
Input:
The first input line contains an integer 'T', the number of test cases.
For each test case:
- The first line contains 'N' (discount interval), 'discount' (percentage), and 'S' (number of products).
- The next line has 'S' space-separated integers for the 'products' array.
- The following line has 'S' space-separated integers for the 'prices' array.
- Then, an integer 'K', the number of customer queries.
For each of the 'K' queries:
- An integer 'S' for the number of distinct products purchased.
- 'S' space-separated integers for the 'productID' array.
- 'S' space-separated integers for the 'quantity' array.
Output:
For each customer in each test case, return a list of the final bill amount considering the discount, in the order bills are generated. Each test case's output should be on a separate line.
Example:
Input:
T = 1
N = 3
discount = 25
S = 2
products = [1, 2]
prices = [100, 200]
K = 2
S = 1
productID = [1]
quantity = [2]
S = 2
productID = [1, 2]
quantity = [1, 1]
Output:
[200.00000, 300.00000]
Constraints:
- 1 ≤ T ≤ 100
- 1 ≤ K ≤ 1000
- 1 ≤ S ≤ 100
- 1 ≤ productID[i], products[i], quantity[i], prices[i] ≤ 1000
Note: You are not required to print anything; just implement the functions to return the results.
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