A train travelling at a speed of 75 mph enters a tunnel 31/2 miles long. The train is 1/4 mile long. How long does it take for the train to pass through the tunnel from the moment the front enters to the moment the rear emerges?

Question

Accepted Answer

Calculate the time taken by a train to pass through a tunnel given its speed, length, and the tunnel's length.

Convert the speed of the train from mph to miles per minute.
Calculate the time taken by the front of the train to enter the tunnel.
Calculate the time taken by the rear of the train to exit the tunnel.
Subtract the time taken by the front from the time taken by the rear to get the total time taken.
Add the units to the final answer.

Accepted Answer

According to above data the required time =(7/2+1/2) /75=(4/75) *3600=192(s) =3 min 12 s

Accepted Answer

Total distance covered = ( 7 + 1 ( miles 2 4 = 15 miles. 4 Therefore Time taken = ( 15 ( hrs 4 x 75 = 1 hrs 20 = ( 1 x 60 ( min. 20 = 3 min.

Accepted Answer

Total distance covered
 = ( 7 + 1 ( miles
 2 4
 = 15 miles.
 4
 Therefore Time taken
 = ( 15 ( hrs
 4 x 75
 = 1 hrs
 20
 = ( 1 x 60 ( min.
 20
 = 3 min.

A train travelling at a speed of 75 mph enters a tunnel 31/2 miles long. The train is 1/4 mile long. How long does it take for the train to pass through the tunnel from the moment the front enters to the moment the rear emerges?

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