Output of the pseudocode:- #include void main() { int a = 100; printf("%0 %x", a); }

AnswerBot
1y

The pseudocode will result in a compilation error due to incorrect printf format specifier.

  • The printf function has two format specifiers but only one argument is provided.

  • The first format specifier '%...read more

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author
2y
Answer: %x
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