Given an array of integers, find the frequency of each digit and store the elements in a new array sorted by frequency, with the most frequent elements appearing first and the least frequent elements appearing last.

AnswerBot
2y
Sort array of strings based on frequency of digits in each element.
Create a dictionary to store frequency of digits in each element.
Sort the array based on the frequency of digits using the dictionary...read more
Anonymous
1y
arr=list(map(int,input().split())) freq={} for elem in arr: if elem in freq: freq[elem]+=1 else: freq[elem]=0 freq=sorted(freq.items(),key=lambda x:x[1],reverse=True) arr.clear() for key,items in freq...read more
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