Asked inWalmart,SDE-2

Maximum Frequency Number Problem Statement

Given an array of integers with numbers in random order, write a program to find and return the number which appears the most frequently in the array.

If multiple elements have the same maximum frequency, return the element that appears first in the array (i.e., the element with the lowest index).

Input

```The first line contains an integer 'T' which denotes the number of test cases. For each test case, the input consists of: - An integer 'N' on the first line denoting the size of the array. - 'N' space-separated integers on the second line denoting the elements of the array.```

Output

```For each test case, print the integer that has the maximum frequency on a new line.```

Example

```Input arr: [1, 2, 3, 1, 2] Output: 1```

Constraints

  • 1 <= T <= 5
  • 1 <= N <= 10000
  • -10^3 <= |arr[i]| <= 10^3

Note

```You are not required to handle input or output operations. Simply implement the required function.```
Kaushaki Kumari
1y
currently not working

int maxcount = 0;

int element_having_max_freq = 0;

for (int i = 0; i < n; i++) {

int count = 0;

for (int j = 0; j < n; j++) {

if (arr[i] == arr[j]) {

count++;

}

}

if (count > maxcount) {

maxcount =...read more

Kaushaki Kumari
1y
currently not working

int maxcount = 0;

int element_having_max_freq = 0;

for (int i = 0; i < n; i++) {

int count = 0;

for (int j = 0; j < n; j++) {

if (arr[i] == arr[j]) {

count++;

}

}

if (count > maxcount) {

maxcount =...read more

Kaushaki Kumari
1y
currently not working

int maxcount = 0;

int element_having_max_freq = 0;

for (int i = 0; i < n; i++) {

int count = 0;

for (int j = 0; j < n; j++) {

if (arr[i] == arr[j]) {

count++;

}

}

if (count > maxcount) {

maxcount =...read more

Kimmi Mams
1y
Input Format:
The first line contains an integer 'T' which denotes the number of test cases or queries to be run. The first line of each test case contains a single integer ‘N’ denoting the size of the...read more
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Walmart SDE-2 Interview Questions
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