Consider the set S of the first 2n numbers, then show that for any subset of size n+1 of the set S, there exists 2 numbers u and v such that u divides v
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For any subset of size n+1 of the set S of the first 2n numbers, there exists 2 numbers u and v such that u divides v.
Divide the set S into two subsets of n numbers each.
By the pigeonhole principle, a...read more
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