Consider the set S of the first 2n numbers, then show that for any subset of size n+1 of the set S, there exists 2 numbers u and v such that u divides v

AnswerBot
1y

For any subset of size n+1 of the set S of the first 2n numbers, there exists 2 numbers u and v such that u divides v.

  • Divide the set S into two subsets of n numbers each.

  • By the pigeonhole principle, a...read more

Help your peers!
Add answer anonymously...
Tower Research Capital LLC Strategist Interview Questions
Stay ahead in your career. Get AmbitionBox app
qr-code
Helping over 1 Crore job seekers every month in choosing their right fit company
65 L+

Reviews

4 L+

Interviews

4 Cr+

Salaries

1 Cr+

Users/Month

Contribute to help millions
Get AmbitionBox app

Made with ❤️ in India. Trademarks belong to their respective owners. All rights reserved © 2024 Info Edge (India) Ltd.

Follow us
  • Youtube
  • Instagram
  • LinkedIn
  • Facebook
  • Twitter