Given a maximum of 100 digit numbers as input, find the difference between the sum of odd and even position digits

Question

Accepted Answer

The program calculates the difference between the sum of odd and even position digits in a given number.

Iterate through each digit of the number
Keep track of the sum of digits at odd positions and even positions separately
Calculate the difference between the two sums

Accepted Answer

#include 
 #include 
 #include 
 
 int main()
 {
  int a = 0,b = 0,i = 0, n;
  char num[100];
  
  printf("Enter the number:");
  scanf("%s",num); //get the input up to 100 digit
  n = strlen(num);
  while(n>0)
  {
  if(i==0) //add even digits when no of digit is even and vise versa
  {
  a+=num[n-1]-48;
  n--;
  i=1;
  }
  else //add odd digits when no of digit is even and vice versa
  {
  b+=num[n-1]-48;
  n--;
  i=0;
  }
  }
  printf("%d",abs(a-b)); //print the difference of odd and even
 
  return 0;
 }

Given a maximum of 100 digit numbers as input, find the difference between the sum of odd and even position digits

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