You are blindfolded and 10 coins are placed in front of you on the table. You are allowed to touch the coins, but can’t tell which way up they are by feel. You are told that there are 5 coins head up, and 5 coins tails up but not which ones are which.
Can you make two piles of coins each with the same number of heads up? You can flip the coins any number of times.

Question

You are blindfolded and 10 coins are placed in front of you on the table. You are allowed to touch the coins, but can’t tell which way up they are by feel. You are told that there are 5 coins head up, and 5 coins tails up but not which ones are which.

Can you make two piles of coins each with the same number of heads up? You can flip the coins any number of times.

Accepted Answer

I took examples there and got the logic of the puzzle. Answer will be yes. Make 2 piles with equal number of coins and in total there will be 5 heads and 5 tails. Now, flip all the coins in one of the pile.Now both piles have the same number of heads. Take an example: suppose one pile have H H T T H and another pile have T H T H T. Now flip the pile one, so pile one will become T T H H T, now both the piles will contain the same number of heads that is 2.

Accepted Answer

Yes, you can achieve this by following these steps:

Divide the 10 coins into two piles, each containing 5 coins.

For the first pile, flip all 5 coins.

For the second pile, leave all 5 coins as they are (assuming they were initially a mix of heads and tails).

Now, both piles will have the same number of heads up (5 each).

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