A district road with a bituminous pavement has a horizontal curve of 1000 m for a design speed of 75 km ph. Then what will be the Super-elevation ?

Question

Accepted Answer

The super-elevation of a district road with a 1000 m horizontal curve for a design speed of 75 km/h.

Super-elevation is the banking of a road to counteract the centrifugal force on vehicles during a curve.
The formula to calculate super-elevation is e = (v^2) / (g * r), where e is the super-elevation, v is the design speed in m/s, g is the acceleration due to gravity, and r is the radius of the curve.
First, convert the design speed from km/h to m/s: 75 km/h = 20.83 m/s.
Next, calculate the radius of the curve using the formula r = (v^2) / (g * tan(theta)), where theta is the angle of the curve.
Assuming a standard angle of 1 in 20 for a district road, the angle of the curve would be approximately 2.86 degrees.
Plugging in the values, r = (20.83^2) / (9.81 * tan(2.86)) = 334.45 m.
Finally, calculate the super-elevation using the formula e = (v^2) / (g * r): e = (20.83^2) / (9.81 * 334.45) = 0.13 or 13%.

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