Sum of Squares of First N Natural Numbers Problem Statement
You are tasked with finding the sum of squares of the first N
natural numbers for given test cases.
Input:
The first line contains an integer 'T', the number of test cases. Each of the next 'T' lines contains a single integer 'N', representing the number for which the sum of squares is to be calculated.
Output:
For each test case, output the sum of squares of the first 'N' natural numbers on a new line.
Example:
Input:
2
4
3
Output:
30
14
Explanation:
For N = 4
, the sum is 1^2 + 2^2 + 3^2 + 4^2 = 30
. For N = 3
, the sum is 1^2 + 2^2 + 3^2 = 14
.
Constraints:
1 ≤ T ≤ 10^4
1 ≤ N ≤ 5*10^5
- Time Limit: 1 sec.
Note:
You are not required to print the expected output, it has already been taken care of. Just implement the function.
girish jagtap
5mo
int in=4;
int op=IntStream.rangeClosed(1, in).map(x->x*x).sum();
System.out.println(op);
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