Energy of orbital of hydrogen atoms ?

Question

Accepted Answer

The energy of the orbital of hydrogen atoms depends on the principal quantum number and can be calculated using the formula -13.6 eV/n^2.

The energy of the orbital is inversely proportional to the square of the principal quantum number (n).
The energy levels of hydrogen atoms are quantized and can be represented by the formula E = -13.6 eV/n^2.
The energy of the orbital decreases as the principal quantum number increases.
The lowest energy level is associated with the ground state (n = 1) and has an energy of -13.6 eV.
Higher energy levels correspond to excited states with larger values of n.

Accepted Answer

Hydrogen atom ke liye orbital k energy different type se hai
1s<2s=2p<3s=3p=3d<4s=4p=4d=4f<
✓ jabki 2s or 2p ka shape different hai
✓ ye shirf hydrogen ke liye h
 ✓ 2s=2p same energy vale orbital ko degenerated orbital khte hai
✓ 2s vala sbse km energy vala orbital hai ise ground state khte hai
 ✓ aage ke sbhi 2s2f- excited state khte hai

Energy of orbital of hydrogen atoms ?

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