Aptitude Question

If there is a frog which can go one step forward with probability 3/4. and one step backward with 1/4. What is expectancy to reach 7 steps forward.

Ala Seif
1y

i_rand = 1000

p = 3/4

path = list()

for i in range(i_rand):

x = [0]

current_pos = 0

for i in range(100):

if current_pos > 0:

coin = s = np.random.binomial(1, p, 1)

if coin ==1:

current_pos += 1

else:

cur...read more

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