Check if an array can be partitioned into two subarrays with equal sum.

• Iterate through the array and calculate the total sum of all elements.

• If the sum is odd, return false as it cannot be divided int...read more

def can_partition(arr):

total_sum = sum(arr)

if total_sum % 2 != 0:

return False

target_sum = total_sum // 2

n = len(arr)

dp = [[False] * (target_sum + 1) for _ in range(n+1)]

for i in range(n+1):

dp[...read more