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10+ Nido Machineries Interview Questions and Answers
Q1. 1) Stress vs strain curve for brittle and ductile material . 2) In finite element method what are shape functions 3) Design a structure which has force at any section because of its self weight but at any secti...
read moreAnswering questions related to stress-strain curves, finite element method, structure design, and weak vs strong form solutions.
1) Stress vs strain curve: Brittle materials have a steep curve with low strain at failure, while ductile materials have a gradual curve with high strain at failure.
2) Shape functions in finite element method: Mathematical functions used to approximate the unknown behavior of a structure within each finite element.
3) Designing a structure with consta...read more
Q2. Axial compressor functioning of GT engines
Axial compressor is a key component in gas turbine engines that compresses air before combustion.
Axial compressor consists of multiple stages of rotating blades and stationary vanes.
Each stage compresses the air and increases its pressure.
The compressed air is then mixed with fuel and ignited in the combustion chamber.
The hot gases produced by combustion expand and drive the turbine, which in turn drives the compressor and the generator.
Efficiency of the axial compressor is c...read more
Q3. Write algorithm to store given data in different formats
Algorithm to store data in different formats
Identify the data types and formats needed
Create a data structure to hold the data
Implement functions to convert data to desired formats
Examples: JSON, CSV, XML, SQL
Consider data security and privacy
Q4. Find the stress and failure condition for a truss system?
To find stress and failure condition for a truss system, analyze the forces acting on each member and calculate the stress using appropriate equations.
Analyze the forces acting on each member of the truss system
Calculate the stress using appropriate equations
Determine the failure condition based on the material properties and stress values
Examples of equations: axial stress = force/area, bending stress = (force x length)/(moment of inertia x distance from neutral axis)
Q5. Natural frequency of beam problem
Natural frequency of a beam refers to the frequency at which the beam vibrates when disturbed from its equilibrium position.
Natural frequency is determined by the material properties and geometry of the beam.
It is important to consider natural frequency when designing structures to avoid resonance.
The formula for natural frequency is f = (1/2π) * √(k/m), where k is the stiffness and m is the mass of the beam.
Example: A bridge designed without considering natural frequency can...read more
Q6. Strength Of material:1. Stress and pressure?difference?
Stress is the force per unit area, while pressure is the force per unit area exerted by a fluid.
Stress is a measure of the internal forces within a material, while pressure is the force exerted on a material from the outside.
Stress is a scalar quantity, while pressure is a vector quantity.
Stress is measured in units of force per unit area, while pressure is measured in units of force per unit area.
Examples of stress include tension, compression, and shear stress, while exampl...read more
Q7. Algorithm to reduce size of stored matrix
Use Singular Value Decomposition (SVD) to reduce matrix size while preserving important information.
SVD breaks down a matrix into its constituent parts, allowing for the removal of less important information.
The resulting smaller matrix can be used to approximate the original matrix with minimal loss of important information.
This technique is commonly used in image compression and data analysis.
Example: A 1000x1000 matrix can be reduced to a 100x100 matrix using SVD.
Q8. Discretization schemes and error analysis on CFD
Discretization schemes are used in CFD to approximate continuous equations. Error analysis is used to evaluate the accuracy of the approximation.
Discretization schemes involve dividing the domain into smaller elements and approximating the equations within each element.
Common schemes include finite difference, finite volume, and finite element methods.
Error analysis involves comparing the numerical solution to the exact solution or a more accurate approximation.
Sources of err...read more
Q9. Ductility of a material? Strain hardening?
Ductility is the ability of a material to deform under tensile stress. Strain hardening is the increase in strength of a material due to plastic deformation.
Ductility allows a material to be drawn into a wire or hammered into a thin sheet without breaking.
Strain hardening occurs when a material is deformed beyond its elastic limit, causing dislocations in the crystal structure.
Examples of ductile materials include copper, gold, and aluminum.
Examples of strain hardening materi...read more
Q10. Predict next few numbers in series
Sorry, I cannot answer this question without knowing the series.
Without knowing the series, it is impossible to predict the next few numbers.
The series could follow any pattern or rule, making it unpredictable without more information.
It is important to have all the necessary data before attempting to make predictions.
Q11. Derive expression of lift over air fail
The expression of lift over air fail is derived using Bernoulli's principle and the equation for lift force.
Lift force is equal to the product of air density, velocity squared, wing area, and lift coefficient.
Airfoil shape and angle of attack affect lift coefficient.
Bernoulli's principle states that as air velocity increases, air pressure decreases.
The pressure difference between the top and bottom of a wing creates lift.
The expression for lift over air fail is lift force div...read more
Q12. Pressure vessel Thick and derivation ?
Thick of pressure vessel is determined by factors like pressure, temperature, material, and safety factor.
Pressure vessel thickness is calculated using various codes and standards like ASME BPVC, EN 13445, PD 5500, etc.
Factors like pressure, temperature, material properties, and safety factor are considered while determining the thickness.
The thickness calculation involves determining the maximum allowable stress, hoop stress, and longitudinal stress.
The thickness also depend...read more
Q13. Stress strain diagram of Al and Cu?
Al and Cu have different stress strain diagrams due to their different material properties.
Al has a higher yield strength and ultimate tensile strength than Cu.
Cu has a higher ductility than Al.
Al has a more linear stress strain curve than Cu.
Cu exhibits necking before fracture, while Al does not.
The modulus of elasticity for Al is higher than Cu.
Q14. Strength of materials
Strength of materials refers to the ability of a material to withstand external forces without breaking or deforming.
It is important in engineering design to ensure that materials used can withstand the expected loads and stresses.
Factors that affect strength of materials include material composition, shape, and size.
Testing methods such as tensile testing and compression testing are used to determine the strength of materials.
Examples of strong materials include steel, titan...read more
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