If you are given an array of 6 numbers 123345 give the logic for finding the duplicate numbers in this array Other technical questions where purely based on what we say previously. When I talked about my course and specializations, all the questions were based on that only. Asked many questions regarding cloud and ethical hacking terminologies

Question

Accepted Answer

Logic to find duplicate numbers in an array of 6 numbers

Iterate through the array and compare each element with the rest of the elements
If a match is found, print the duplicate number
Use nested loops to compare all elements
Alternatively, use a hash table to keep track of seen elements

Accepted Answer

array = [1, 2, 3, 3, 4, 5]
for i in range(0,len(array)):
for j in range(i+1, len(array)):
if array[i] == array[j]:
print(array[j])

Accepted Answer

create an array and empty stack(duplicate=[])
make for loop  start from 0 and end to arr.length
inside for loop build a if condition( arr.indexOf(arr[i])!== i  && duplicate.indexOf(arr[i]) === -1)
then when condition run found any repeated element push in stack

Accepted Answer

3 is the duplicate number

Accepted Answer

3 number are duplicate number

Accepted Answer

first define a function and use its parameter as (arr)
then create an empty dict to store seen numbers seen={ }
create an empty list for duplicates = [ ]
then use for loop
for num in arr
if num in seen
if num not in duplicates
duplicates.append(num)
else
seen[num]=True
return duplicates
now we need to test the function
numbers= [1,2,3,3,4,5]
duplicate_num = find_duplicates(numbers)
print(duplicate_num)

your ans will be 3

Accepted Answer

3 is the doublicate number

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