Rectangles In NxN Board
You are given a positive integer N. Your task is to find the number of possible rectangles, excluding squares, in a N x N chessboard.

Example:

Let’s assume that we have a chessboard of dimension 4x4, i.e. N = 4. Then the rectangles can have the following possible dimensions: {1*2, 1*3, 1*4, 2*1, ……, 2*4, ………,4*4}. So, the total number of rectangles in the chessboard is 70.

Input format:

The very first line of input contains an integer T’ denoting the number of test cases. The first line of every test case contains an integer ‘N’ denoting the dimension of the chessboard.

Output format:

For each test case, print the number of possible rectangles, excluding squares, in a N x N chessboard. Output for each test case is printed on a separate line.

Note:

The result can be very large. So, print the answer modulo 1000000007. You do not need to print anything, it has already been taken care of. Just return the number of possible rectangles.

Constraints:

1

Question

Rectangles In NxN Board

You are given a positive integer N. Your task is to find the number of possible rectangles, excluding squares, in a N x N chessboard.

Example:

Let’s assume that we have a chessboard of dimension 4x4, i.e. N = 4. Then the rectangles can have the following possible dimensions: {1*2, 1*3, 1*4, 2*1, ……, 2*4, ………,4*4}. So, the total number of rectangles in the chessboard is 70.

Input format:

The very first line of input contains an integer T’ denoting the number of test cases. 

The first line of every test case contains an integer ‘N’ denoting the dimension of the chessboard.

Output format:

For each test case, print the number of possible rectangles, excluding squares, in a N x N chessboard.

Output for each test case is printed on a separate line.

Note:

The result can be very large. So, print the answer modulo 1000000007.

You do not need to print anything, it has already been taken care of. Just return the number of possible rectangles.

Constraints:

1 <= T <= 10 
1 <= N <= 5 * 10^4

Time Limit: 1 sec

Accepted Answer

Using Basic Maths

A simple approach to solve this problem is to find the total number of possible rectangles, including squares, and then subtract the number of possible squares.
We can easily determine the total number of rectangles if we think of a rectangle as a pair of horizontal lines and a pair of vertical lines, intersecting at four points.
The given board will have (N+1) horizontal and (N+1) vertical lines.
So, the total number of rectangles (including squares) would be the number of ways to choose two distinct horizontal lines and two distinct vertical lines.
This can be found by using combinations as: (N + 1)C2 * (N + 1)C2, where ‘C’ stands for combination. This is equal to (N * (N + 1) / 2) * (N * (N + 1) / 2) = (N * (N + 1) / 2) ^ 2
Now, to determine the number of possible squares, we try to determine the pattern between the dimension of the square and the number of such squares present in the N x N board.
- Number of squares with dimension 1x1 = N^2
- Number of squares with dimension 2x2 = (N - 1)^2
- Number of squares with dimension 3x3 = (N - 2)^2
- And so on, till number of squares with dimension NxN = (N - (N-1))^2 = 1^2
Adding the above values, we get total number of possible squares in a N x N board = 1^2 + 2^2 + ……. (N-1)^2 + N^2 = N * (N + 1) * (2 * N + 1) / 6 (using the formula for sum of the squares of first ‘N’ natural numbers).
Therefore, the number of rectangles (excluding squares) = (N*(N+1)/2)^2 - (N*(N + 1)*(2*N + 1)/6). This can be easily calculated in constant time.

Space Complexity: O(1)Explanation:

O(1)

Only constant extra space is required for calculating the number of possible rectangles. Hence, the space complexity is O(1).

Time Complexity: O(1)Explanation:

O(1)

Only constant time is required for calculating the number of possible rectangles. Hence, the time complexity is O(1).

Java (SE 1.8)

/*

    Time Complexity - O(1)

    Space Complexity - O(1)

*/



public class Solution 

{

	public static int countRectangles(int n) 

    {

        // Find the number of rectangles (including squares) i.e. (N*(N+1)/2) ^ 2.

        long rect = ((((long)n * (long)(n + 1))%1000000007) / 2);

       

		rect = (rect%1000000007 * rect%1000000007) % 1000000007;

        

        // Find the number of possible squares present in the N x N board i.e. N*(N + 1)*(2*N + 1)/6.

		long sqr = ((long)n * (long)(n + 1) * (long)(2L *n + 1)) / 6;

        sqr %= 1000000007;

     

        // Find the number of rectangles (excluding squares)

        long ans = (rect - sqr + 1000000007) % 1000000007;

      

        return (int) ans % 1000000007;

	}

}

Python (3.5)

'''
    Time Complexity - O(1)
    Space Complexity - O(1)
'''

MOD = 1000000007


def countRectangles(n):
    # Find the number of rectangles (including squares) i.e. (N*(N+1)/2) ^ 2.
    rectangles = (n*(n+1)) // 2

    rectangles = (rectangles*rectangles) % MOD

    # Find the number of possible squares present in the N x N board i.e. N*(N + 1)*(2*N + 1)/6.
    squares = (n*(n+1)*(2*n+1)) // 6
    squares %= MOD

    # Find the number of rectangles (excluding squares).
    ans = (rectangles-squares+MOD) % MOD

    return ans

C++ (g++ 5.4)

/*

    Time Complexity - O(1)

    Space Complexity - O(1)

*/



const int MOD = 1000000007;



int countRectangles(int n)

{

    // Find the number of rectangles (including squares) i.e. (N*(N+1)/2) ^ 2.

    int rectangles = ((n * ((long long)n + 1)) / 2) % MOD;



    rectangles = ((long long)rectangles * rectangles) % MOD;



    // Find the number of possible squares present in the N x N board i.e. N*(N + 1)*(2*N + 1)/6.

    int squares = ((n * ((long long)n + 1) * (2LL * n + 1)) / 6) % MOD;



    // Find the number of rectangles (excluding squares).

    int ans = ((long long)rectangles - squares + MOD) % MOD;



    return ans;

}

You are given a positive integer N. Your task is to find the number of possible rectangles, excluding squares, in a N x N chessboard.

Example:

Input format:

Output format:

Note:

Constraints:

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