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Find frequency of 2 in sorted array of integers in log(n) time.
Use binary search to find first and last occurrence of 2 in array.
Calculate frequency by subtracting last index from first index and addi...read more
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Time complexity isO(log)n
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Time complexity isO(log)n
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Time complexity isO(log)n
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Time complexity is o(logn)
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Time complexity is O(log(n).
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Ues binary search to find and last occurrence of 2in array
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Time complexity is 0
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Time complexity is 0(log(n))
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Time complexity is o(login)
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Calculate frequency by subtracting last index from first index and adding 1
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Calculate frequency by subtracting last index from first index and adding 1
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Do this without traversing the complete array expected time complexity is less then 0(n)
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Calculate frequency by substacting last index from 1 index and adding1
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Time complexity is O(login)
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Frequency of 2in the array is<
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Use binary search to find first and last occurrence of in array
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Calculate frequency by substacting last index from 1 index and adding1
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Given sorted array arr positive
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Calculate frequency by subtracting last index from first index and adding 1.
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Time complexity is O(log(n))
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Use binary search to find first and last occurrence of 2 in arrayUse binary search to find first and last occurrence of 2 in array
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- Use binary search to find the first occurrence of 2 in the array.Use binary search to find the last occurrence of 2 in the array.Return the difference of the two indices plus 1.
For example, if the arr...read more
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- Use binary search to find first and last occurrence of 2 in array.Calculate frequency by subtracting last index from first index and adding 1.Time complexity is O(log(n)).
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// C++ program to count occurrences of an element
#include<bits/.h>
using
namespace
std;
// Returns number of times x occurs in arr[0.]
int(int
arr[], int
n, int
x)
{
int
res = 0;
for
(int
i=0; i<n; i++)
...read more
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First occurence,last occurence
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Time complexity is O(log(n)).
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Last occurrance - first occurrance+1
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Add 2 array then divided by total number of araay
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Last occurrence - first occurrence + 1
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(last_occurence - first_occurence + 1)
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LastLast occurrence -first occurrence+1
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Last occurrence -first occurrence+1
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Th e idea take from last occurence
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Last occurrence and first occurrence+1 or any alphabet like (X or Y) which means that can be mention anything in first and last .
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Last_occurence-frist_occurence+1
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(last_occurence - first_occurence + 1)
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