Please explain which among the following will give complete hydrolysis, partial hydrolysis and no hydrolysis and also explain the reason for that. Chloride, cyanide and hydride

Question

Accepted Answer

Chloride undergoes complete hydrolysis, cyanide undergoes partial hydrolysis, and hydride undergoes no hydrolysis.

Chloride undergoes complete hydrolysis because it forms HCl in water.
Cyanide undergoes partial hydrolysis because it forms HCN in water.
Hydride undergoes no hydrolysis because it does not react with water.

Accepted Answer

1. Chloride (Cl-): Chloride ions undergo complete hydrolysis in water to form hydrochloric acid (HCl) and hydroxide ions (OH-). The reaction is: Cl- + H2O → HCl + OH-. This is because chloride ions are the conjugate bases of strong acids (like HCl), so they are very weak bases and readily accept protons from water molecules.

2. Cyanide (CN-): Cyanide ions undergo partial hydrolysis in water to form hydrocyanic acid (HCN) and hydroxide ions (OH-). The reaction is: CN- + H2O → HCN + OH-. This is because cyanide ions are the conjugate bases of weak acids (like HCN), so they are weak bases and only partially accept protons from water molecules.

3. Hydride (H-): Hydride ions do not undergo hydrolysis in water under normal conditions. This is because hydride ions are very strong bases, and water is not acidic enough to protonate them. Therefore, hydride ions do not react with water to any significant extent.

In summary, chloride undergoes complete hydrolysis because it comes from a strong acid, cyanide undergoes partial hydrolysis because it comes from a weak acid, and hydride does not undergo hydrolysis because it is a very strong base and water is not acidic enough to react with it.

Please explain which among the following will give complete hydrolysis, partial hydrolysis and no hydrolysis and also explain the reason for that. Chloride, cyanide and hydride

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