Sum of Even & Odd Digits Problem Statement
Create a program that accepts an integer N
and outputs two sums: the sum of all even digits and the sum of all odd digits found in the integer.
Explanation:
Digits refer to the numbers themselves, not their positional values. For example, if N
is "13245", the even digits are 2 & 4, and the odd digits are 1, 3 & 5.
Input:
Integer N
Output:
Sum_of_Even_Digits Sum_of_Odd_Digits
First print the sum of even digits, followed by the sum of odd digits, separated by a space.
Example:
Input:
13245
Output:
6 9
Explanation:
In the input 13245
, the even digits are 2 and 4, summing to 6. The odd digits are 1, 3, and 5, summing to 9.
Constraints:
0 <= N <= 10^8
import java.util.Scanner;
public class SumEvenAndOddDigits {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
System.out.print("Enter an integer N: ");
int N = scanner.nextInt();
int evenSum = 0;
int oddSum = 0;
while (N != 0) {
int digit = N % 10;
if (digit % 2 == 0) {
evenSum += digit;
} else {
oddSum += digit;
}
N /= 10;
}
System.out.println("Sum of even digits: " + evenSum);
System.out.println("Sum of odd digits: " + oddSum);
}
}
a = int(input()) n = [] for _ in range(a): m = int(input()) n.append(m) even = 0 odd = 0 for x in range(0, len(n)): if n[x] % 2 == 0: even = even + n[x] else: odd = odd + n[x] print(even) print(odd) M...read more
Namepace SumOfEvenAndOddDigits
{
class Program
{
static void Main(string[] args)
{
Console.Write("Enter an integer: ");
int number = int.Parse(Console.ReadLine());
int sumEven = 0;
int sumOdd = 0;
// C...read more
def sum_of_even_and_odd_digits(N):
even_sum = 0
odd_sum = 0
while N > 0:
digit = N % 10 # Extract the last digit
if digit % 2 == 0: # Check if the digit is even
even_sum += digit
else:
odd_sum += digi...read more
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