Aptitude

Showing 1 - 10 of 116 questions

1

Today it is Thursday.After 132 days,it will be

a

Monday

b

Sunday

c

Wednesday

d

Thursday

Explanation:

Since each day of the week is repeated after 7 days.

After 133 days,it will be thursday.

So one day before that would be Wednesday.

2

A train 120 meters long is running with a speed of 60 km/hr. In what time will it pass a boy who is running at 6 km/hr in the direction opposite to that in which the train is going?

a

6.54 sec

b

44.32 sec

c

55 sec

d

30.2 sec

Speed of train relative to boy= (60 + 6) km/hr = 66 km/hr

= [66 xx 5/18] m/sec = [55/3] m/sec.

Time taken to pass the boy= [120 xx 3/55] sec = 6.54 seconds

3

Devesh can cover a certain distance in 1 hour 24 minutes by covering two-third of the distance at 6 km/hour and the rest at 7 km/hr. Calculate total distance.

a

8 km

b

9 km

c

6 km

d

7/5 km

Let the total distance be x , then

[{(2/3) x }/6 ] + [{(1/3) x }/7 ] = 7/5

=> x/9 + x/21 = 7/5

=> 7x = 63

=> x = 9

Therefore , total distance = 6 km

4

Find the H.C.F, if the numbers are in the ratio of 4 : 5 : 6 and their L.C.M. is 2400.

a

35

b

20

c

40

d

67

Let the numbers be 3x, 4x and 5x.

Then,their L.C.M. = 120x.

So, 120x = 2400 or x = 20.

=>The numbers are (4 x 20), (5 x 20) and (6 x 20).

Hence, required H.C.F = 20.

5

What is the value of c , If 8 is 4% of a, and 4 is 8% of b. c equals b/a.

a

12

b

1/4

c

0.155

d

None of these

Let be the 4% of a is 4a/100.

Since this equals 8, we have 4a/100=8.

Solving for a yields a=8×(100/4)=200.

Also, 8% of b equals 8b/100, and this equals 4.

Hence, we have (8/100)×b=4.

Solving for b yields  b = 50.

Now, c=b/a=50/200=1/4.

6

P and Q take part in 100 m race. P runs at 6kmph. P gives Q a start of 8 m and still beats him by 8 seconds. The speed of Q is:

a

6.14 kmph

b

15.2 kmph

c

5 kmph

d

4.86 kmph

speed =( 6**5/18)m/sec) = (30/18) m/sec

Time taken by P to cover 100 m = (100 ** 18/30)m/sec =60 sec

Time taken by Q to cover 92 m = (60 + 8) = 68 sec.

Q's speed =("Distance"/"Time"**18/5) kmph =(92/68 ** 18/5) kmph = 4.86kmph.

7

Find the speed of the boat in still water, if a boat covers a certain distance upstream in 2 hours, while it comes back in 11/2 hours. If the speed of the stream be 3 kmph.

a

12 Kmph

b

18 Kmph

c

21 Kmph

d

24 Kmph

Let the speed of the boat in still water be x kmph. Then,

Speed downstream = (x + 3) kmph,

Speed upstream = (x - 3)kmph.

(x - 3) * 2 = (x + 3) * 3/2

4x - 12 = 3x + 9

x = 21kmph.

8

In covering a distance of 40 km, Kamlesh takes 2 hours more than Pankaj. If Kamlesh doubles his speed, then he would take 1 hour less than Pankaj. Then what is Kamlesh's speed?

a

11 Kmph

b

5 Kmph

c

9 Kmph

d

6 Kmph

Let Kamlesh’s speed be x km/hr.

Then, 40/x - 40/(2x) = 4

8x = 40

x = 5 km/hr

9

Find the speed of the train, if a train 142 m long passes a pole in 6 seconds.

a

77.2 km/hr

b

79.6 km/hr

c

84.9 km/hr

d

79.2 km/hr

Speed = [142/6] m/sec

= [23.6 ** 18/5] km/hr

= 84.9 km/hr

10

The rate at which a sum becomes four times of itself in 25 years at S.I.,will be:

a

30%

b

25%

c

12%

d

49%

Rate = [100 ** (S.I.) / P**T] %
= [100 ** (3x) / x ** 25]% = 12%